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Lever math.
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tedbear
Posted 4/13/2014 09:47 (#3812673 - in reply to #3812259)
Subject: RE: Lever math.


Near Intersection of I-35 & I-90 Southern Mn.
Draw a picture. Total length of arm is 25". Pivot is 15" from one end. So pivot is 10" from the other end.

One end is 10/25 which equals .4 or 40%.

Other end is 15/25 which equals .6 or 60%.

40% + 60% = 100% (Check)

So a 40 pound kid on one end of this seesaw should balance a 60 pound kid on the other end (disregarding the extra weight of the longer arm itself).
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