Please check my math, but here's the way I'd understand it.

#2 (?) beans = 60# @ 13% moisture

Therefore, there are 52.20 lbs of dry matter (= 0% moisture) in a bus of sb (60 x 1.0 - .13 = 52.2).

Then, if you divide the remaining dry matter (52.2) into the original poundage (60 lb), you'd arrive at 1.15% shrink for each percent of moisture. That's on soybeans.

Do the same math on corn & you come up with 1.18%, which is the real physical shrink, though grain buyers (= elevators etc) shrink corn around here by 1.4% to cover "other" losses (= make profit).

I believe this is all correct.