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| I can't understand the math to obtain that values, for me it's like follows.
32% is 11.04 lb/gal with 20% w/w water and 80 % w/w product (45.1% Ammonia Nitrate + 34.8% Urea)
28% is 10.66 lb/gal with 30% w/w water and 70% w/w product (39.5% Ammonia Nitrate + 30.5% Urea)
If you consider 1 gal of 32% and diluted with “X” lbs of water to have 70% of product like in 28%, you have:
Lbs of product in 32% / Lbs of mix = 0.7
Lbs of product in 32%= 80%*11.04
Lbs of mix = 11.04 lbs of a 32% gal + X lbs of water added
80%*11.04/(11.04 + X lbs of water) = 0.7 rearranging,
(80%*11.04/0.7) - 11.04 = X = 1.577 lb of water/8.34 = 0.189 gall of water to be added/gall of 32% to convert 32% to 28%
Edit, I correct a mistake as I had used specific gravity value instead density, sorry.
Edited by Roger416 3/20/2013 12:48
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32% uan to 28%
