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Mount Vernon, WA | You don't understand sir, so let me illustrate this way. Say you have a solid steel pipe sticking out of the ground, surrounded by a puddle of water. This pipe is 3 feet long, 2 feet of which are exposed to the air (1 foot in the ground). You wish to shorten said pipe by one foot, to leave only one foot exposed. You get out your torch and cut the pipe. After cutting said pipe, what is the temperature of this remaining length of pipe immediately next to the cut area? I bet you wouldn't touch it!
In your arguments about the Deutz engine, you are claiming that the pipe in my example above is the same temperature for its entire length as the water (or air) that it is submerged in or surrounded by. It would be if you let it set for an hour, but not immediately after you cut it with a torch.
Now then, the pipe is the cylinder wall, and the ground end of the pipe is the side of the cylinder wall surrounded by coolant (or air in the case of a Deutz). The torch is the heat of combustion. Is the cylinder wall temp 300 degrees during combustion? Of course not, it's much higher. If you wish to argue that the cylinder wall is not 1 foot thick, that's fine, cut the pipe as close as you can to ground level. When you're done cutting, the water will be sizzling like a bowl of rice crispies right after the milk is poured.
My point is that the cylinder wall (and piston) temps are very similar between the air cooled and liquid cooled engines. If my explanation above doesn't convince you of that, then I give up.
Edited by Bern 7/3/2012 11:42
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