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Leesburg, Ohio | Deaner: The volume of a cone is 1/3 the volume of a cylinder the same diameter and height. So if you know the bin diameter and the height of grain on the wall, and the approximate depth of the cone (this is easy when it stops running out of the sump), and if you know how to calculate the volume of a cylinder, and if you know that a cubic foot is .8 bushels, and a bin ring is either 32" or 44" tall, you can then do the math.
If you just remember the formula for finding volume of a cylinder is "Pi R squared H", you can do about anything you need for finding bushels in a bin.
Pi R Squared gives you area of a circle. Times H gives you volume. Times .8 converts cuft to bushels.
or pi x Radius squared x Height x .8
Example: 24' diameter bin, grain is two (narrow) rings deep when it stops running out the center. (one narrow ring is 32", or 2.67' tall, x 2 rings, so H= 5.33' )
First find the area: 3.14 x 12 x 12 = 452 sq ft
Then the volume: 452 x 5.33' = 2410 cuft
Then convert to bu: 2410 x .8 = 1928 bu in two rings
Then subtract 1/3 to take out center cone: 1928-643 = 1285 bu
Experience tells me that by the time we pull the intermediate sumps open and run those empty, we will have about 1000 bu left in that size bin.
And yes, experience tells me that a 21' bin holds about 750/ring, a 24' bin holds about 950/ring, and a 27' bin holds about 1200/ring...
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