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Speed of an Irrigation Pivot
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Billybob
Posted 6/19/2006 18:26 (#20623 - in reply to #20482)
Subject: C x P x H = D


Constant x Percentage x Hours = Degrees

This pivot make 360 degrees in 12 hrs.

.3 x 100% x 12 hrs = 360 degrees

Let say the pivot stops because of flat tire. I can measure the top ring on the pivot to get the degrees left to complete cycle. Lets say 55% left to being done. How long will that take at say 14% ( that is about 1 inch of water for me. )

C x P x H = D

.3 x 14 x__ = 55 degrees

Answer .3 x 14 = 4.2 55/4.2 = 13.1 hrs.

It is 3 p.m. When do I want to start the pivot ? Now ? No.

It will be done at 4 a.m.

Wait till 8 p.m. and it will be done at 9 a.m. the next morning.

or

I can start it now and just slow it down. How much slower. Just put the hours in to figure the percentage needed.

C x P x H = D

.3 x __ x 18 hrs ( that is from 3 .pm. to 9a.m. the next morning) = 55 degrees

answer .3 x 18 = 5.4 55 degrees/ 5.4 = 10.2 %


How do I know what the constant will be for any pivot ?

The easiest way I know of is to time the pivot for 360 degree circle at only one timer setting, like 14 %. It is best to do it on the second or later circle for the season. The pivot packs the ground and the time does change a little. We can get with in 15 min. of when our pivot will be done. We don't always need to know, but some times we do need to know.
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