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How would you go about getting this auger to turn slower?
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hillfarmer
Posted 10/31/2025 06:06 (#11419288 - in reply to #11419194)
Subject: RE: How would you go about getting this auger to turn slower?



WTW - 10/30/2025 23:57

Johnienhuis - 10/30/2025 18:38

The auger in the picture fills a dryer and as far as I can tell it currently turns the auger about 400rpm. To me this seems like it should be turning closer to 200rpm. It’s a 10 inch auger so it might even be able to spin slower than 200 and still keep up, but 200rpm is what I figured was practical.

Anyways, I haven’t been able to find pulleys that would go from 1750 to 200 without a jack shaft. So I am just looking for peoples ideas on how they would go about doing this, and if you would add a jack shaft any ideas on fabricating it would be helpful.

Motor shaft is 1 3/8 and the auger shaft is 1 1/4. We also don’t have 3 phase available at this location.


We have numerous augers in our grain drying system that use a chain reduction for the final drive in combination with a 90 degree gearbox and appropriate sized pulleys to achieve the desired speed. Works for us.

For a 10 hp input I would likely go to a #80 chain for the final reduction. If your existing pulleys result in a 400 rpm ouput, a sprocket ratio of 1 to 2 would get you down to 200 rpm. 100 rpm on a 10" auger would probably output 600 to 700 bushels per hour. We are running a pto 10" auger at 60 rpm on the output of our dryer and it will take in excess of 500 bushels per hour.

If you want to make the chain drive more or less maintenance free build a box to enclose it and put corn head grease in it.


Picture "1730" has a yellow cord looks like it goes in and out of the hopper ??
the 90 degree gear boxes are 1 to 1 ?? a 2 or 3 to 1 would be nice
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