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SC IA | I can't resist a planter math problem. Follow my logic, so you can check my work.
I am assuming by "driver shaft" you're referring to the hex shaft that runs out of the seed transmission to the row units. Also assume we're talking about the finger pickup corn meter. Plates or cups will be different.
To make the math practical and get more workable numbers lets assume a 12R30" planter. And a population of 32,000. 7000 planters have a 12-finger seed pickup, and correct me if I'm wrong, but I believe the hex shaft and seed meter are both 19 tooth sprockets, so a 1:1 ratio there. So each turn of the hex shaft gets you 12 seeds.
4.5mph is: (6.6feet per second) x (60 seconds) is 396 feet of row per minute. 396 feet of row x 30 feet of swath = 11880 square feet, or 0.27 acres per minute.
In our elapsed 60 seconds, if planting at 32000, the planter should have dispensed 8727 seeds. 8727/12 (row count) is 727 seeds/row/minute. 727/12 (seeds per shaft turn) gives us 60.6 RPM on the shaft.
Do you agree?
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